With reference to SL Bug # 2063 which deals with bringing some kind of notification alert whenever an unhandled python exception occurs, I had a few doubts. There are two approaches that I can think of. 1. Any unhandled python exception is always logged. Thus, if we can check whenever logging.ERROR has been called, there ,an exception has occured .Thus if we introduce a flag which attains True value when an exception occurs, and by checking the value of the flag in a GUI file we can generate an alert/notification. For this purpose, I have tried to get a git diff of the sugar.logger . However, I have a doubt whether it is through this logger.py file through which logging is taken place . I see the file not being imported by journal files,etc. diff --git a/logger.py b/logger.py index 6a6b574..fd079dc 100644 --- a/logger.py +++ b/logger.py @@ -43,6 +43,9 @@ _LEVELS = { 'trace': TRACE, 'all': 0, } + +CHECK_ALERT = False + logging.addLevelName(TRACE, 'TRACE') @@ -57,8 +60,9 @@ def get_logs_dir(): def set_level(level): if level in _LEVELS: logging.getLogger('').setLevel(_LEVELS[level]) - return - + alert_log_exception(level) + return + try: logging.getLogger('').setLevel(int(level)) except ValueError: @@ -203,3 +207,8 @@ def trace(logger=None, logger_name=None, skip_args=None, skip_kwargs=None, return res return decorator.decorator(_trace) + +def alert_log_exception(level): + if level == 'error' + CHECK_ALERT = True + -- 1.7.0.4 2. Alternatively, if we can make a new file that reads the shell.log line by line and whenever ERROR: is encountered, an alert is raised. However, for this the new file has to be active at all times. It would be great if you could shed some light on what approach should I follow or suggest an alternative way to this problem. Waiting for your response and valuable suggestions, Regards, Mukul Gupta Research Engineer,SEETA